-4(b+2)=40+2b

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Solution for -4(b+2)=40+2b equation: 



-4(b+2)=40+2b

We move all terms to the left:

-4(b+2)-(40+2b)=0

We add all the numbers together, and all the variables

-4(b+2)-(2b+40)=0

We multiply parentheses

-4b-(2b+40)-8=0

We get rid of parentheses

-4b-2b-40-8=0

We add all the numbers together, and all the variables

-6b-48=0

We move all terms containing b to the left, all other terms to the right

-6b=48

b=48/-6

b=-8

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