-4(b+4)-3b+32=21

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Solution for -4(b+4)-3b+32=21 equation: 



-4(b+4)-3b+32=21

We move all terms to the left:

-4(b+4)-3b+32-(21)=0

We add all the numbers together, and all the variables

-3b-4(b+4)+11=0

We multiply parentheses

-3b-4b-16+11=0

We add all the numbers together, and all the variables

-7b-5=0

We move all terms containing b to the left, all other terms to the right

-7b=5

b=5/-7

b=-5/7

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