-4(b+5)=2(1-4b)-2

Solution for -4(b+5)=2(1-4b)-2 equation:

-4(b+5)=2(1-4b)-2

We move all terms to the left:

-4(b+5)-(2(1-4b)-2)=0

We add all the numbers together, and all the variables

-4(b+5)-(2(-4b+1)-2)=0

We multiply parentheses

-4b-(2(-4b+1)-2)-20=0


We calculate terms in parentheses: -(2(-4b+1)-2), so:

2(-4b+1)-2

We multiply parentheses

-8b+2-2

We add all the numbers together, and all the variables

-8b

Back to the equation:

-(-8b)


We get rid of parentheses

-4b+8b-20=0

We add all the numbers together, and all the variables

4b-20=0

We move all terms containing b to the left, all other terms to the right

4b=20

b=20/4

b=5