-4(b-2)+4b=10b+3

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Solution for -4(b-2)+4b=10b+3 equation: 



-4(b-2)+4b=10b+3

We move all terms to the left:

-4(b-2)+4b-(10b+3)=0

We add all the numbers together, and all the variables

4b-4(b-2)-(10b+3)=0

We multiply parentheses

4b-4b-(10b+3)+8=0

We get rid of parentheses

4b-4b-10b-3+8=0

We add all the numbers together, and all the variables

-10b+5=0

We move all terms containing b to the left, all other terms to the right

-10b=-5

b=-5/-10

b=1/2

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