-4(b-2)=-4(b-8)-8b

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Solution for -4(b-2)=-4(b-8)-8b equation:



-4(b-2)=-4(b-8)-8b
We move all terms to the left:
-4(b-2)-(-4(b-8)-8b)=0
We multiply parentheses
-4b-(-4(b-8)-8b)+8=0
We calculate terms in parentheses: -(-4(b-8)-8b), so:
-4(b-8)-8b
We add all the numbers together, and all the variables
-8b-4(b-8)
We multiply parentheses
-8b-4b+32
We add all the numbers together, and all the variables
-12b+32
Back to the equation:
-(-12b+32)
We get rid of parentheses
-4b+12b-32+8=0
We add all the numbers together, and all the variables
8b-24=0
We move all terms containing b to the left, all other terms to the right
8b=24
b=24/8
b=3

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