-4(c+1)+2c=3(2b-1)

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Solution for -4(c+1)+2c=3(2b-1) equation:


Simplifying
-4(c + 1) + 2c = 3(2b + -1)

Reorder the terms:
-4(1 + c) + 2c = 3(2b + -1)
(1 * -4 + c * -4) + 2c = 3(2b + -1)
(-4 + -4c) + 2c = 3(2b + -1)

Combine like terms: -4c + 2c = -2c
-4 + -2c = 3(2b + -1)

Reorder the terms:
-4 + -2c = 3(-1 + 2b)
-4 + -2c = (-1 * 3 + 2b * 3)
-4 + -2c = (-3 + 6b)

Solving
-4 + -2c = -3 + 6b

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -2c = -3 + 4 + 6b

Combine like terms: -4 + 4 = 0
0 + -2c = -3 + 4 + 6b
-2c = -3 + 4 + 6b

Combine like terms: -3 + 4 = 1
-2c = 1 + 6b

Divide each side by '-2'.
c = -0.5 + -3b

Simplifying
c = -0.5 + -3b

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