-4(c+3)+2c=2(10-c)

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Solution for -4(c+3)+2c=2(10-c) equation:


Simplifying
-4(c + 3) + 2c = 2(10 + -1c)

Reorder the terms:
-4(3 + c) + 2c = 2(10 + -1c)
(3 * -4 + c * -4) + 2c = 2(10 + -1c)
(-12 + -4c) + 2c = 2(10 + -1c)

Combine like terms: -4c + 2c = -2c
-12 + -2c = 2(10 + -1c)
-12 + -2c = (10 * 2 + -1c * 2)
-12 + -2c = (20 + -2c)

Add '2c' to each side of the equation.
-12 + -2c + 2c = 20 + -2c + 2c

Combine like terms: -2c + 2c = 0
-12 + 0 = 20 + -2c + 2c
-12 = 20 + -2c + 2c

Combine like terms: -2c + 2c = 0
-12 = 20 + 0
-12 = 20

Solving
-12 = 20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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