-4(c-3)=2(c+6)

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Solution for -4(c-3)=2(c+6) equation:


Simplifying
-4(c + -3) = 2(c + 6)

Reorder the terms:
-4(-3 + c) = 2(c + 6)
(-3 * -4 + c * -4) = 2(c + 6)
(12 + -4c) = 2(c + 6)

Reorder the terms:
12 + -4c = 2(6 + c)
12 + -4c = (6 * 2 + c * 2)
12 + -4c = (12 + 2c)

Add '-12' to each side of the equation.
12 + -12 + -4c = 12 + -12 + 2c

Combine like terms: 12 + -12 = 0
0 + -4c = 12 + -12 + 2c
-4c = 12 + -12 + 2c

Combine like terms: 12 + -12 = 0
-4c = 0 + 2c
-4c = 2c

Solving
-4c = 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
-4c + -2c = 2c + -2c

Combine like terms: -4c + -2c = -6c
-6c = 2c + -2c

Combine like terms: 2c + -2c = 0
-6c = 0

Divide each side by '-6'.
c = 0

Simplifying
c = 0

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