-4(h+5)=-3(2-h)+14

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Solution for -4(h+5)=-3(2-h)+14 equation: 



-4(h+5)=-3(2-h)+14

We move all terms to the left:

-4(h+5)-(-3(2-h)+14)=0

We add all the numbers together, and all the variables

-4(h+5)-(-3(-1h+2)+14)=0

We multiply parentheses

-4h-(-3(-1h+2)+14)-20=0



We calculate terms in parentheses: -(-3(-1h+2)+14), so:

-3(-1h+2)+14

We multiply parentheses

3h-6+14

We add all the numbers together, and all the variables

3h+8

Back to the equation:

-(3h+8)



We get rid of parentheses

-4h-3h-8-20=0

We add all the numbers together, and all the variables

-7h-28=0

We move all terms containing h to the left, all other terms to the right

-7h=28

h=28/-7

h=-4

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