-4(k+5)=5/3(3k-12)

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Solution for -4(k+5)=5/3(3k-12) equation: 



-4(k+5)=5/3(3k-12)

We move all terms to the left:

-4(k+5)-(5/3(3k-12))=0



Domain of the equation: 3(3k-12))!=0

k∈R



We multiply parentheses

-4k-(5/3(3k-12))-20=0

We multiply all the terms by the denominator


-4k*3(3k-12))-(5-20*3(3k-12))=0

Wy multiply elements

-12k^2(3-60k(3=0

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