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-4(k+5)=5/3(3k-12)
We move all terms to the left:
-4(k+5)-(5/3(3k-12))=0
Domain of the equation: 3(3k-12))!=0We multiply parentheses
k∈R
-4k-(5/3(3k-12))-20=0
We multiply all the terms by the denominator
-4k*3(3k-12))-(5-20*3(3k-12))=0
Wy multiply elements
-12k^2(3-60k(3=0
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