-4(m+2)+2m=1/2(10-12m)-3

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Solution for -4(m+2)+2m=1/2(10-12m)-3 equation: 



-4(m+2)+2m=1/2(10-12m)-3

We move all terms to the left:

-4(m+2)+2m-(1/2(10-12m)-3)=0



Domain of the equation: 2(10-12m)-3)!=0

m∈R



We add all the numbers together, and all the variables

-4(m+2)+2m-(1/2(-12m+10)-3)=0

We add all the numbers together, and all the variables

2m-4(m+2)-(1/2(-12m+10)-3)=0

We multiply parentheses

2m-4m-(1/2(-12m+10)-3)-8=0

We multiply all the terms by the denominator


2m*2(-12m+10)-3)-4m*2(-12m-12m+10)-3)-(1-8*2(+10)-3)=0

We add all the numbers together, and all the variables

2m*2(-12m+10)-3)-4m*2(-24m+10)-3)-(1-8*210-3)=0

We add all the numbers together, and all the variables

-24m+2m*2(-12m+10)-3)-4m*2(=0

Wy multiply elements

4m^2(--3)-24m-4m*2(=0

We add all the numbers together, and all the variables

4m^23-24m-4m*2(=0

Wy multiply elements

4m^23-8m^2-24m=0

We do not support empression: m^23

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