-4(n+1)-(n+2)=

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Solution for -4(n+1)-(n+2)= equation:


Simplifying
-4(n + 1) + -1(n + 2) = 0

Reorder the terms:
-4(1 + n) + -1(n + 2) = 0
(1 * -4 + n * -4) + -1(n + 2) = 0
(-4 + -4n) + -1(n + 2) = 0

Reorder the terms:
-4 + -4n + -1(2 + n) = 0
-4 + -4n + (2 * -1 + n * -1) = 0
-4 + -4n + (-2 + -1n) = 0

Reorder the terms:
-4 + -2 + -4n + -1n = 0

Combine like terms: -4 + -2 = -6
-6 + -4n + -1n = 0

Combine like terms: -4n + -1n = -5n
-6 + -5n = 0

Solving
-6 + -5n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -5n = 0 + 6

Combine like terms: -6 + 6 = 0
0 + -5n = 0 + 6
-5n = 0 + 6

Combine like terms: 0 + 6 = 6
-5n = 6

Divide each side by '-5'.
n = -1.2

Simplifying
n = -1.2

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