-4(n-3)+10=2

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Solution for -4(n-3)+10=2 equation: 



-4(n-3)+10=2

We move all terms to the left:

-4(n-3)+10-(2)=0

We add all the numbers together, and all the variables

-4(n-3)+8=0

We multiply parentheses

-4n+12+8=0

We add all the numbers together, and all the variables

-4n+20=0

We move all terms containing n to the left, all other terms to the right

-4n=-20

n=-20/-4

n=+5

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