-4(n-3)+3(1-7n)=40

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Solution for -4(n-3)+3(1-7n)=40 equation: 



-4(n-3)+3(1-7n)=40

We move all terms to the left:

-4(n-3)+3(1-7n)-(40)=0

We add all the numbers together, and all the variables

-4(n-3)+3(-7n+1)-40=0

We multiply parentheses

-4n-21n+12+3-40=0

We add all the numbers together, and all the variables

-25n-25=0

We move all terms containing n to the left, all other terms to the right

-25n=25

n=25/-25

n=-1

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