-4(n-3)-2(n+4)=-8

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Solution for -4(n-3)-2(n+4)=-8 equation: 



-4(n-3)-2(n+4)=-8

We move all terms to the left:

-4(n-3)-2(n+4)-(-8)=0

We add all the numbers together, and all the variables

-4(n-3)-2(n+4)+8=0

We multiply parentheses

-4n-2n+12-8+8=0

We add all the numbers together, and all the variables

-6n+12=0

We move all terms containing n to the left, all other terms to the right

-6n=-12

n=-12/-6

n=+2

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