-4(n-4)=2(n-1)

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Solution for -4(n-4)=2(n-1) equation: 


Simplifying
-4(n + -4) = 2(n + -1)

Reorder the terms:
-4(-4 + n) = 2(n + -1)
(-4 * -4 + n * -4) = 2(n + -1)
(16 + -4n) = 2(n + -1)

Reorder the terms:
16 + -4n = 2(-1 + n)
16 + -4n = (-1 * 2 + n * 2)
16 + -4n = (-2 + 2n)

Solving
16 + -4n = -2 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
16 + -4n + -2n = -2 + 2n + -2n

Combine like terms: -4n + -2n = -6n
16 + -6n = -2 + 2n + -2n

Combine like terms: 2n + -2n = 0
16 + -6n = -2 + 0
16 + -6n = -2

Add '-16' to each side of the equation.
16 + -16 + -6n = -2 + -16

Combine like terms: 16 + -16 = 0
0 + -6n = -2 + -16
-6n = -2 + -16

Combine like terms: -2 + -16 = -18
-6n = -18

Divide each side by '-6'.
n = 3

Simplifying
n = 3

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