-4(n-5)=2(1-3n)

Solution for -4(n-5)=2(1-3n) equation:

-4(n-5)=2(1-3n)

We move all terms to the left:

-4(n-5)-(2(1-3n))=0

We add all the numbers together, and all the variables

-4(n-5)-(2(-3n+1))=0

We multiply parentheses

-4n-(2(-3n+1))+20=0


We calculate terms in parentheses: -(2(-3n+1)), so:

2(-3n+1)

We multiply parentheses

-6n+2

Back to the equation:

-(-6n+2)


We get rid of parentheses

-4n+6n-2+20=0

We add all the numbers together, and all the variables

2n+18=0

We move all terms containing n to the left, all other terms to the right

2n=-18

n=-18/2

n=-9