-4(n-8)-4n=-3(n-4)-n

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Solution for -4(n-8)-4n=-3(n-4)-n equation: 



-4(n-8)-4n=-3(n-4)-n

We move all terms to the left:

-4(n-8)-4n-(-3(n-4)-n)=0

We add all the numbers together, and all the variables

-4n-4(n-8)-(-3(n-4)-n)=0

We multiply parentheses

-4n-4n-(-3(n-4)-n)+32=0



We calculate terms in parentheses: -(-3(n-4)-n), so:

-3(n-4)-n

We add all the numbers together, and all the variables

-1n-3(n-4)

We multiply parentheses

-1n-3n+12

We add all the numbers together, and all the variables

-4n+12

Back to the equation:

-(-4n+12)



We add all the numbers together, and all the variables

-8n-(-4n+12)+32=0

We get rid of parentheses

-8n+4n-12+32=0

We add all the numbers together, and all the variables

-4n+20=0

We move all terms containing n to the left, all other terms to the right

-4n=-20

n=-20/-4

n=+5

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