-4(r+1)-r=5(1+r)+3r

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Solution for -4(r+1)-r=5(1+r)+3r equation: 



-4(r+1)-r=5(1+r)+3r

We move all terms to the left:

-4(r+1)-r-(5(1+r)+3r)=0

We add all the numbers together, and all the variables

-4(r+1)-r-(5(r+1)+3r)=0

We add all the numbers together, and all the variables

-1r-4(r+1)-(5(r+1)+3r)=0

We multiply parentheses

-1r-4r-(5(r+1)+3r)-4=0



We calculate terms in parentheses: -(5(r+1)+3r), so:

5(r+1)+3r

We add all the numbers together, and all the variables

3r+5(r+1)

We multiply parentheses

3r+5r+5

We add all the numbers together, and all the variables

8r+5

Back to the equation:

-(8r+5)



We add all the numbers together, and all the variables

-5r-(8r+5)-4=0

We get rid of parentheses

-5r-8r-5-4=0

We add all the numbers together, and all the variables

-13r-9=0

We move all terms containing r to the left, all other terms to the right

-13r=9

r=9/-13

r=-9/13

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