-4(r+2)=3(2-2r)

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Solution for -4(r+2)=3(2-2r) equation: 



-4(r+2)=3(2-2r)

We move all terms to the left:

-4(r+2)-(3(2-2r))=0

We add all the numbers together, and all the variables

-4(r+2)-(3(-2r+2))=0

We multiply parentheses

-4r-(3(-2r+2))-8=0



We calculate terms in parentheses: -(3(-2r+2)), so:

3(-2r+2)

We multiply parentheses

-6r+6

Back to the equation:

-(-6r+6)



We get rid of parentheses

-4r+6r-6-8=0

We add all the numbers together, and all the variables

2r-14=0

We move all terms containing r to the left, all other terms to the right

2r=14

r=14/2

r=7

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