-4(r-3)=3(r+4)

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Solution for -4(r-3)=3(r+4) equation: 



-4(r-3)=3(r+4)

We move all terms to the left:

-4(r-3)-(3(r+4))=0

We multiply parentheses

-4r-(3(r+4))+12=0



We calculate terms in parentheses: -(3(r+4)), so:

3(r+4)

We multiply parentheses

3r+12

Back to the equation:

-(3r+12)



We get rid of parentheses

-4r-3r-12+12=0

We add all the numbers together, and all the variables

-7r=0

r=0/-7

r=0

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