-4(t+2)-t-4=-5(t+4)+8

Solution for -4(t+2)-t-4=-5(t+4)+8 equation:

-4(t+2)-t-4=-5(t+4)+8

We move all terms to the left:

-4(t+2)-t-4-(-5(t+4)+8)=0

We add all the numbers together, and all the variables

-1t-4(t+2)-(-5(t+4)+8)-4=0

We multiply parentheses

-1t-4t-(-5(t+4)+8)-8-4=0


We calculate terms in parentheses: -(-5(t+4)+8), so:

-5(t+4)+8

We multiply parentheses

-5t-20+8

We add all the numbers together, and all the variables

-5t-12

Back to the equation:

-(-5t-12)


We add all the numbers together, and all the variables

-5t-(-5t-12)-12=0

We get rid of parentheses

-5t+5t+12-12=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0