-4(t+2)-t-5=-5(t+5)+12

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Solution for -4(t+2)-t-5=-5(t+5)+12 equation: 



-4(t+2)-t-5=-5(t+5)+12

We move all terms to the left:

-4(t+2)-t-5-(-5(t+5)+12)=0

We add all the numbers together, and all the variables

-1t-4(t+2)-(-5(t+5)+12)-5=0

We multiply parentheses

-1t-4t-(-5(t+5)+12)-8-5=0



We calculate terms in parentheses: -(-5(t+5)+12), so:

-5(t+5)+12

We multiply parentheses

-5t-25+12

We add all the numbers together, and all the variables

-5t-13

Back to the equation:

-(-5t-13)



We add all the numbers together, and all the variables

-5t-(-5t-13)-13=0

We get rid of parentheses

-5t+5t+13-13=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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