-4(t+2)=5(t+-3)

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Solution for -4(t+2)=5(t+-3) equation: 



-4(t+2)=5(t+-3)

We move all terms to the left:

-4(t+2)-(5(t+-3))=0

We add all the numbers together, and all the variables

-4(t+2)-(5(t-3))=0

We multiply parentheses

-4t-(5(t-3))-8=0



We calculate terms in parentheses: -(5(t-3)), so:

5(t-3)

We multiply parentheses

5t-15

Back to the equation:

-(5t-15)



We get rid of parentheses

-4t-5t+15-8=0

We add all the numbers together, and all the variables

-9t+7=0

We move all terms containing t to the left, all other terms to the right

-9t=-7

t=-7/-9

t=7/9

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