-4(t+3)-t-2=-5(t+4)+6

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Solution for -4(t+3)-t-2=-5(t+4)+6 equation: 



-4(t+3)-t-2=-5(t+4)+6

We move all terms to the left:

-4(t+3)-t-2-(-5(t+4)+6)=0

We add all the numbers together, and all the variables

-1t-4(t+3)-(-5(t+4)+6)-2=0

We multiply parentheses

-1t-4t-(-5(t+4)+6)-12-2=0



We calculate terms in parentheses: -(-5(t+4)+6), so:

-5(t+4)+6

We multiply parentheses

-5t-20+6

We add all the numbers together, and all the variables

-5t-14

Back to the equation:

-(-5t-14)



We add all the numbers together, and all the variables

-5t-(-5t-14)-14=0

We get rid of parentheses

-5t+5t+14-14=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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