-4(t-3)+10=-2(5+6t)

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Solution for -4(t-3)+10=-2(5+6t) equation:



-4(t-3)+10=-2(5+6t)
We move all terms to the left:
-4(t-3)+10-(-2(5+6t))=0
We add all the numbers together, and all the variables
-4(t-3)-(-2(6t+5))+10=0
We multiply parentheses
-4t-(-2(6t+5))+12+10=0
We calculate terms in parentheses: -(-2(6t+5)), so:
-2(6t+5)
We multiply parentheses
-12t-10
Back to the equation:
-(-12t-10)
We add all the numbers together, and all the variables
-4t-(-12t-10)+22=0
We get rid of parentheses
-4t+12t+10+22=0
We add all the numbers together, and all the variables
8t+32=0
We move all terms containing t to the left, all other terms to the right
8t=-32
t=-32/8
t=-4

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