-4(t-4)-16=2(t+3)

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Solution for -4(t-4)-16=2(t+3) equation: 



-4(t-4)-16=2(t+3)

We move all terms to the left:

-4(t-4)-16-(2(t+3))=0

We multiply parentheses

-4t-(2(t+3))+16-16=0



We calculate terms in parentheses: -(2(t+3)), so:

2(t+3)

We multiply parentheses

2t+6

Back to the equation:

-(2t+6)



We add all the numbers together, and all the variables

-4t-(2t+6)=0

We get rid of parentheses

-4t-2t-6=0

We add all the numbers together, and all the variables

-6t-6=0

We move all terms containing t to the left, all other terms to the right

-6t=6

t=6/-6

t=-1

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