-4(t-5)+4=3(t+1)

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Solution for -4(t-5)+4=3(t+1) equation: 



-4(t-5)+4=3(t+1)

We move all terms to the left:

-4(t-5)+4-(3(t+1))=0

We multiply parentheses

-4t-(3(t+1))+20+4=0



We calculate terms in parentheses: -(3(t+1)), so:

3(t+1)

We multiply parentheses

3t+3

Back to the equation:

-(3t+3)



We add all the numbers together, and all the variables

-4t-(3t+3)+24=0

We get rid of parentheses

-4t-3t-3+24=0

We add all the numbers together, and all the variables

-7t+21=0

We move all terms containing t to the left, all other terms to the right

-7t=-21

t=-21/-7

t=+3

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