-4(t-5)+7t=6t-3

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Solution for -4(t-5)+7t=6t-3 equation: 



-4(t-5)+7t=6t-3

We move all terms to the left:

-4(t-5)+7t-(6t-3)=0

We add all the numbers together, and all the variables

7t-4(t-5)-(6t-3)=0

We multiply parentheses

7t-4t-(6t-3)+20=0

We get rid of parentheses

7t-4t-6t+3+20=0

We add all the numbers together, and all the variables

-3t+23=0

We move all terms containing t to the left, all other terms to the right

-3t=-23

t=-23/-3

t=7+2/3

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