-4(u+1)+6u=2(u+2)-8

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Solution for -4(u+1)+6u=2(u+2)-8 equation:


Simplifying
-4(u + 1) + 6u = 2(u + 2) + -8

Reorder the terms:
-4(1 + u) + 6u = 2(u + 2) + -8
(1 * -4 + u * -4) + 6u = 2(u + 2) + -8
(-4 + -4u) + 6u = 2(u + 2) + -8

Combine like terms: -4u + 6u = 2u
-4 + 2u = 2(u + 2) + -8

Reorder the terms:
-4 + 2u = 2(2 + u) + -8
-4 + 2u = (2 * 2 + u * 2) + -8
-4 + 2u = (4 + 2u) + -8

Reorder the terms:
-4 + 2u = 4 + -8 + 2u

Combine like terms: 4 + -8 = -4
-4 + 2u = -4 + 2u

Add '4' to each side of the equation.
-4 + 4 + 2u = -4 + 4 + 2u

Combine like terms: -4 + 4 = 0
0 + 2u = -4 + 4 + 2u
2u = -4 + 4 + 2u

Combine like terms: -4 + 4 = 0
2u = 0 + 2u
2u = 2u

Add '-2u' to each side of the equation.
2u + -2u = 2u + -2u

Combine like terms: 2u + -2u = 0
0 = 2u + -2u

Combine like terms: 2u + -2u = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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