-4(u+2)=7u-2+2(2u+3)

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Solution for -4(u+2)=7u-2+2(2u+3) equation: 



-4(u+2)=7u-2+2(2u+3)

We move all terms to the left:

-4(u+2)-(7u-2+2(2u+3))=0

We multiply parentheses

-4u-(7u-2+2(2u+3))-8=0



We calculate terms in parentheses: -(7u-2+2(2u+3)), so:

7u-2+2(2u+3)

determiningTheFunctionDomain
7u+2(2u+3)-2

We multiply parentheses

7u+4u+6-2

We add all the numbers together, and all the variables

11u+4

Back to the equation:

-(11u+4)



We get rid of parentheses

-4u-11u-4-8=0

We add all the numbers together, and all the variables

-15u-12=0

We move all terms containing u to the left, all other terms to the right

-15u=12

u=12/-15

u=-4/5

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