-4(v+1)+6=2(v+2)-8

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Solution for -4(v+1)+6=2(v+2)-8 equation: 



-4(v+1)+6=2(v+2)-8

We move all terms to the left:

-4(v+1)+6-(2(v+2)-8)=0

We multiply parentheses

-4v-(2(v+2)-8)-4+6=0



We calculate terms in parentheses: -(2(v+2)-8), so:

2(v+2)-8

We multiply parentheses

2v+4-8

We add all the numbers together, and all the variables

2v-4

Back to the equation:

-(2v-4)



We add all the numbers together, and all the variables

-4v-(2v-4)+2=0

We get rid of parentheses

-4v-2v+4+2=0

We add all the numbers together, and all the variables

-6v+6=0

We move all terms containing v to the left, all other terms to the right

-6v=-6

v=-6/-6

v=1

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