-4(v+1)+6v=2(v+2)

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Solution for -4(v+1)+6v=2(v+2) equation: 



-4(v+1)+6v=2(v+2)

We move all terms to the left:

-4(v+1)+6v-(2(v+2))=0

We add all the numbers together, and all the variables

6v-4(v+1)-(2(v+2))=0

We multiply parentheses

6v-4v-(2(v+2))-4=0



We calculate terms in parentheses: -(2(v+2)), so:

2(v+2)

We multiply parentheses

2v+4

Back to the equation:

-(2v+4)



We add all the numbers together, and all the variables

2v-(2v+4)-4=0

We get rid of parentheses

2v-2v-4-4=0

We add all the numbers together, and all the variables

-8!=0

There is no solution for this equation

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