-4(v+1)+6v=2(v+2)-8

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Solution for -4(v+1)+6v=2(v+2)-8 equation:


Simplifying
-4(v + 1) + 6v = 2(v + 2) + -8

Reorder the terms:
-4(1 + v) + 6v = 2(v + 2) + -8
(1 * -4 + v * -4) + 6v = 2(v + 2) + -8
(-4 + -4v) + 6v = 2(v + 2) + -8

Combine like terms: -4v + 6v = 2v
-4 + 2v = 2(v + 2) + -8

Reorder the terms:
-4 + 2v = 2(2 + v) + -8
-4 + 2v = (2 * 2 + v * 2) + -8
-4 + 2v = (4 + 2v) + -8

Reorder the terms:
-4 + 2v = 4 + -8 + 2v

Combine like terms: 4 + -8 = -4
-4 + 2v = -4 + 2v

Add '4' to each side of the equation.
-4 + 4 + 2v = -4 + 4 + 2v

Combine like terms: -4 + 4 = 0
0 + 2v = -4 + 4 + 2v
2v = -4 + 4 + 2v

Combine like terms: -4 + 4 = 0
2v = 0 + 2v
2v = 2v

Add '-2v' to each side of the equation.
2v + -2v = 2v + -2v

Combine like terms: 2v + -2v = 0
0 = 2v + -2v

Combine like terms: 2v + -2v = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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