-4(v+1)=6v-8+2(2v+7)

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Solution for -4(v+1)=6v-8+2(2v+7) equation: 



-4(v+1)=6v-8+2(2v+7)

We move all terms to the left:

-4(v+1)-(6v-8+2(2v+7))=0

We multiply parentheses

-4v-(6v-8+2(2v+7))-4=0



We calculate terms in parentheses: -(6v-8+2(2v+7)), so:

6v-8+2(2v+7)

determiningTheFunctionDomain
6v+2(2v+7)-8

We multiply parentheses

6v+4v+14-8

We add all the numbers together, and all the variables

10v+6

Back to the equation:

-(10v+6)



We get rid of parentheses

-4v-10v-6-4=0

We add all the numbers together, and all the variables

-14v-10=0

We move all terms containing v to the left, all other terms to the right

-14v=10

v=10/-14

v=-5/7

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