-4(v+1)=v-6+2(5v+7)

Solution for -4(v+1)=v-6+2(5v+7) equation:

-4(v+1)=v-6+2(5v+7)

We move all terms to the left:

-4(v+1)-(v-6+2(5v+7))=0

We multiply parentheses

-4v-(v-6+2(5v+7))-4=0


We calculate terms in parentheses: -(v-6+2(5v+7)), so:

v-6+2(5v+7)

determiningTheFunctionDomain
v+2(5v+7)-6

We multiply parentheses

v+10v+14-6

We add all the numbers together, and all the variables

11v+8

Back to the equation:

-(11v+8)


We get rid of parentheses

-4v-11v-8-4=0

We add all the numbers together, and all the variables

-15v-12=0

We move all terms containing v to the left, all other terms to the right

-15v=12

v=12/-15

v=-4/5