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-4(v+2)+6v=2(v+2)-8
We move all terms to the left:
-4(v+2)+6v-(2(v+2)-8)=0
We add all the numbers together, and all the variables
6v-4(v+2)-(2(v+2)-8)=0
We multiply parentheses
6v-4v-(2(v+2)-8)-8=0
We calculate terms in parentheses: -(2(v+2)-8), so:We add all the numbers together, and all the variables
2(v+2)-8
We multiply parentheses
2v+4-8
We add all the numbers together, and all the variables
2v-4
Back to the equation:
-(2v-4)
2v-(2v-4)-8=0
We get rid of parentheses
2v-2v+4-8=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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