-4(v+2)=-5(4v-2)+4v

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Solution for -4(v+2)=-5(4v-2)+4v equation: 



-4(v+2)=-5(4v-2)+4v

We move all terms to the left:

-4(v+2)-(-5(4v-2)+4v)=0

We multiply parentheses

-4v-(-5(4v-2)+4v)-8=0



We calculate terms in parentheses: -(-5(4v-2)+4v), so:

-5(4v-2)+4v

We add all the numbers together, and all the variables

4v-5(4v-2)

We multiply parentheses

4v-20v+10

We add all the numbers together, and all the variables

-16v+10

Back to the equation:

-(-16v+10)



We get rid of parentheses

-4v+16v-10-8=0

We add all the numbers together, and all the variables

12v-18=0

We move all terms containing v to the left, all other terms to the right

12v=18

v=18/12

v=1+1/2

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