-4(v+2)=2v-3+2(3v+2)

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Solution for -4(v+2)=2v-3+2(3v+2) equation:



-4(v+2)=2v-3+2(3v+2)
We move all terms to the left:
-4(v+2)-(2v-3+2(3v+2))=0
We multiply parentheses
-4v-(2v-3+2(3v+2))-8=0
We calculate terms in parentheses: -(2v-3+2(3v+2)), so:
2v-3+2(3v+2)
determiningTheFunctionDomain 2v+2(3v+2)-3
We multiply parentheses
2v+6v+4-3
We add all the numbers together, and all the variables
8v+1
Back to the equation:
-(8v+1)
We get rid of parentheses
-4v-8v-1-8=0
We add all the numbers together, and all the variables
-12v-9=0
We move all terms containing v to the left, all other terms to the right
-12v=9
v=9/-12
v=-3/4

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