-4(v+2)=2v-3+2(3v+2)

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Solution for -4(v+2)=2v-3+2(3v+2) equation: 



-4(v+2)=2v-3+2(3v+2)

We move all terms to the left:

-4(v+2)-(2v-3+2(3v+2))=0

We multiply parentheses

-4v-(2v-3+2(3v+2))-8=0



We calculate terms in parentheses: -(2v-3+2(3v+2)), so:

2v-3+2(3v+2)

determiningTheFunctionDomain
2v+2(3v+2)-3

We multiply parentheses

2v+6v+4-3

We add all the numbers together, and all the variables

8v+1

Back to the equation:

-(8v+1)



We get rid of parentheses

-4v-8v-1-8=0

We add all the numbers together, and all the variables

-12v-9=0

We move all terms containing v to the left, all other terms to the right

-12v=9

v=9/-12

v=-3/4

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