-4(v+2)=3v-4+2(4v+1)

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Solution for -4(v+2)=3v-4+2(4v+1) equation: 



-4(v+2)=3v-4+2(4v+1)

We move all terms to the left:

-4(v+2)-(3v-4+2(4v+1))=0

We multiply parentheses

-4v-(3v-4+2(4v+1))-8=0



We calculate terms in parentheses: -(3v-4+2(4v+1)), so:

3v-4+2(4v+1)

determiningTheFunctionDomain
3v+2(4v+1)-4

We multiply parentheses

3v+8v+2-4

We add all the numbers together, and all the variables

11v-2

Back to the equation:

-(11v-2)



We get rid of parentheses

-4v-11v+2-8=0

We add all the numbers together, and all the variables

-15v-6=0

We move all terms containing v to the left, all other terms to the right

-15v=6

v=6/-15

v=-2/5

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