-4(w+3)(-w+6)=0

Solution for -4(w+3)(-w+6)=0 equation:

-4(w+3)(-w+6)=0

We add all the numbers together, and all the variables

-4(w+3)(-1w+6)=0

We multiply parentheses ..

-4(-1w^2+6w-3w+18)=0

We multiply parentheses

4w^2-24w+12w-72=0

We add all the numbers together, and all the variables

4w^2-12w-72=0

a = 4; b = -12; c = -72;
Δ = b2-4ac
Δ = -122-4·4·(-72)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-36}{2*4}=\frac{-24}{8}
=-3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+36}{2*4}=\frac{48}{8}
=6
$