-4(w+3)=4w-2+5(2w+1)

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Solution for -4(w+3)=4w-2+5(2w+1) equation: 



-4(w+3)=4w-2+5(2w+1)

We move all terms to the left:

-4(w+3)-(4w-2+5(2w+1))=0

We multiply parentheses

-4w-(4w-2+5(2w+1))-12=0



We calculate terms in parentheses: -(4w-2+5(2w+1)), so:

4w-2+5(2w+1)

determiningTheFunctionDomain
4w+5(2w+1)-2

We multiply parentheses

4w+10w+5-2

We add all the numbers together, and all the variables

14w+3

Back to the equation:

-(14w+3)



We get rid of parentheses

-4w-14w-3-12=0

We add all the numbers together, and all the variables

-18w-15=0

We move all terms containing w to the left, all other terms to the right

-18w=15

w=15/-18

w=-5/6

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