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-4(x+)=5/3(3x-12)
We move all terms to the left:
-4(x+)-(5/3(3x-12))=0
Domain of the equation: 3(3x-12))!=0We add all the numbers together, and all the variables
x∈R
-4(+x)-(5/3(3x-12))=0
We multiply parentheses
-4x-(5/3(3x-12))=0
We multiply all the terms by the denominator
-4x*3(3x-12))-(5=0
Wy multiply elements
-12x^2(3=0
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