-4(x+1)+3(3x-3)=4(x-3)+10

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Solution for -4(x+1)+3(3x-3)=4(x-3)+10 equation: 



-4(x+1)+3(3x-3)=4(x-3)+10

We move all terms to the left:

-4(x+1)+3(3x-3)-(4(x-3)+10)=0

We multiply parentheses

-4x+9x-(4(x-3)+10)-4-9=0



We calculate terms in parentheses: -(4(x-3)+10), so:

4(x-3)+10

We multiply parentheses

4x-12+10

We add all the numbers together, and all the variables

4x-2

Back to the equation:

-(4x-2)



We add all the numbers together, and all the variables

5x-(4x-2)-13=0

We get rid of parentheses

5x-4x+2-13=0

We add all the numbers together, and all the variables

x-11=0

We move all terms containing x to the left, all other terms to the right

x=11

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