-4(x+1)+3(3x-3)=4(x-5)+12

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Solution for -4(x+1)+3(3x-3)=4(x-5)+12 equation:



-4(x+1)+3(3x-3)=4(x-5)+12
We move all terms to the left:
-4(x+1)+3(3x-3)-(4(x-5)+12)=0
We multiply parentheses
-4x+9x-(4(x-5)+12)-4-9=0
We calculate terms in parentheses: -(4(x-5)+12), so:
4(x-5)+12
We multiply parentheses
4x-20+12
We add all the numbers together, and all the variables
4x-8
Back to the equation:
-(4x-8)
We add all the numbers together, and all the variables
5x-(4x-8)-13=0
We get rid of parentheses
5x-4x+8-13=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5

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