-4(x+1)=-2(3x-5)+8x

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Solution for -4(x+1)=-2(3x-5)+8x equation: 



-4(x+1)=-2(3x-5)+8x

We move all terms to the left:

-4(x+1)-(-2(3x-5)+8x)=0

We multiply parentheses

-4x-(-2(3x-5)+8x)-4=0



We calculate terms in parentheses: -(-2(3x-5)+8x), so:

-2(3x-5)+8x

We add all the numbers together, and all the variables

8x-2(3x-5)

We multiply parentheses

8x-6x+10

We add all the numbers together, and all the variables

2x+10

Back to the equation:

-(2x+10)



We get rid of parentheses

-4x-2x-10-4=0

We add all the numbers together, and all the variables

-6x-14=0

We move all terms containing x to the left, all other terms to the right

-6x=14

x=14/-6

x=-2+1/3

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