-4(x+2)-3(x-2)=7(x+1)

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Solution for -4(x+2)-3(x-2)=7(x+1) equation: 



-4(x+2)-3(x-2)=7(x+1)

We move all terms to the left:

-4(x+2)-3(x-2)-(7(x+1))=0

We multiply parentheses

-4x-3x-(7(x+1))-8+6=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We add all the numbers together, and all the variables

-7x-(7x+7)-2=0

We get rid of parentheses

-7x-7x-7-2=0

We add all the numbers together, and all the variables

-14x-9=0

We move all terms containing x to the left, all other terms to the right

-14x=9

x=9/-14

x=-9/14

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