-4(x+3)+x=3(x+2)-19-6x

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Solution for -4(x+3)+x=3(x+2)-19-6x equation: 



-4(x+3)+x=3(x+2)-19-6x

We move all terms to the left:

-4(x+3)+x-(3(x+2)-19-6x)=0

We add all the numbers together, and all the variables

x-4(x+3)-(3(x+2)-19-6x)=0

We multiply parentheses

x-4x-(3(x+2)-19-6x)-12=0



We calculate terms in parentheses: -(3(x+2)-19-6x), so:

3(x+2)-19-6x

determiningTheFunctionDomain
3(x+2)-6x-19

We add all the numbers together, and all the variables

-6x+3(x+2)-19

We multiply parentheses

-6x+3x+6-19

We add all the numbers together, and all the variables

-3x-13

Back to the equation:

-(-3x-13)



We add all the numbers together, and all the variables

-3x-(-3x-13)-12=0

We get rid of parentheses

-3x+3x+13-12=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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