-4(x-1)+3x=-3x(x+2)-3

Solution for -4(x-1)+3x=-3x(x+2)-3 equation:

-4(x-1)+3x=-3x(x+2)-3

We move all terms to the left:

-4(x-1)+3x-(-3x(x+2)-3)=0

We add all the numbers together, and all the variables

3x-4(x-1)-(-3x(x+2)-3)=0

We multiply parentheses

3x-4x-(-3x(x+2)-3)+4=0


We calculate terms in parentheses: -(-3x(x+2)-3), so:

-3x(x+2)-3

We multiply parentheses

-3x^2-6x-3

Back to the equation:

-(-3x^2-6x-3)


We add all the numbers together, and all the variables

-(-3x^2-6x-3)-1x+4=0

We get rid of parentheses

3x^2+6x-1x+3+4=0

We add all the numbers together, and all the variables

3x^2+5x+7=0

a = 3; b = 5; c = +7;
Δ = b2-4ac
Δ = 52-4·3·7
Δ = -59
Delta is less than zero, so there is no solution for the equation