-4(x-11)(x-3)=0

Solution for -4(x-11)(x-3)=0 equation:

-4(x-11)(x-3)=0

We multiply parentheses ..

-4(+x^2-3x-11x+33)=0

We multiply parentheses

-4x^2+12x+44x-132=0

We add all the numbers together, and all the variables

-4x^2+56x-132=0

a = -4; b = 56; c = -132;
Δ = b2-4ac
Δ = 562-4·(-4)·(-132)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-32}{2*-4}=\frac{-88}{-8}
=+11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+32}{2*-4}=\frac{-24}{-8}
=+3
$